How to use Python to convert an octal to a decimal
These first lines take any decimal number and convert it to any desired number base
def dec2base():
a = int(input('Enter decimal number: \t'))
d = int(input('Enter expected base: \t'))
b = ""
while a != 0:
x = '0123456789ABCDEF'
c = a % d
c1 = x[c]
b = str(c1) + b
a = int(a // d)
return (b)
The second lines do the same but for a given range and a given decimal
def dec2base_R():
a = int(input('Enter start decimal number:\t'))
e = int(input('Enter end decimal number:\t'))
d = int(input('Enter expected base:\t'))
for i in range (a, e):
b = ""
while i != 0:
x = '0123456789ABCDEF'
c = i % d
c1 = x[c]
b = str(c1) + b
i = int(i // d)
return (b)
The third lines convert from any base back to decimal
def todec():
c = int(input('Enter base of the number to convert to decimal:\t'))
a = (input('Then enter the number:\t ')).upper()
b = list(a)
s = 0
x = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F']
for pos, digit in enumerate(b[-1::-1]):
y = x.index(digit)
if int(y)/c >= 1:
print('Invalid input!!!')
break
s = (int(y) * (c**pos)) + s
return (s)
Note: I also have the GUI version if anyone needs them
From decimal to octal:
oct(42) # '052'
Octal to decimal
int('052', 8) # 42
If you want to return octal as a string then you might want to wrap it in str
.