How to wait until an element is present in Selenium?

WebDriverWait wait = new WebDriverWait(driver,5)
wait.until(ExpectedConditions.visibilityOf(element));

you can use this as some time before loading whole page code gets executed and throws and error. time is in second

You need to call ignoring with exception to ignore while the WebDriver will wait.

FluentWait<WebDriver> fluentWait = new FluentWait<>(driver)
        .withTimeout(30, TimeUnit.SECONDS)
        .pollingEvery(200, TimeUnit.MILLISECONDS)
        .ignoring(NoSuchElementException.class);

See the documentation of FluentWait for more info. But beware that this condition is already implemented in ExpectedConditions so you should use

WebElement element = (new WebDriverWait(driver, 10))
   .until(ExpectedConditions.elementToBeClickable(By.id("someid")));

*Update for newer versions of Selenium:

withTimeout(long, TimeUnit) has become withTimeout(Duration)
pollingEvery(long, TimeUnit) has become pollingEvery(Duration)

So the code will look as such:

FluentWait<WebDriver> fluentWait = new FluentWait<>(driver)
        .withTimeout(Duration.ofSeconds(30)
        .pollingEvery(Duration.ofMillis(200)
        .ignoring(NoSuchElementException.class);

Basic tutorial for waiting can be found here.

Let me recommend you using Selenide library. It allows writing much more concise and readable tests. It can wait for presence of elements with much shorter syntax:

$("#elementId").shouldBe(visible);

Here is a sample project for testing Google search: https://github.com/selenide-examples/google