How would you implement the IEnumerator interface?

Just implement the IEnumerable<T> interface. No need to implement the IEnumerator<T> unless you want to do some special things in the enumerator, which for your case doesn't seem to be needed.

public class Mapper<K,T> : IEnumerable<T> {
    public IEnumerator<T> GetEnumerator()
    {
        return KToTMap.Values.GetEnumerator();
    }
}

and that's it.

First, don't make your collection object implement IEnumerator<>. This leads to bugs. (Consider the situation where two threads are iterating over the same collection).

Implementing an enumerator correctly turns out to be non-trivial, so C# 2.0 added special language support for doing it, based on the 'yield return' statement.

Raymond Chen's recent series of blog posts ("The implementation of iterators in C# and its consequences") is a good place to get up to speed.

• Part 1: https://web.archive.org/web/20081216071723/http://blogs.msdn.com/oldnewthing/archive/2008/08/12/8849519.aspx
• Part 2: https://web.archive.org/web/20080907004812/http://blogs.msdn.com/oldnewthing/archive/2008/08/13/8854601.aspx
• Part 3: https://web.archive.org/web/20080824210655/http://blogs.msdn.com/oldnewthing/archive/2008/08/14/8862242.aspx
• Part 4: https://web.archive.org/web/20090207130506/http://blogs.msdn.com/oldnewthing/archive/2008/08/15/8868267.aspx

Use yield return.

What is the yield keyword used for in C#?

CreateEnumerable() returns an IEnumerable which implements GetEnumerator()

public class EasyEnumerable : IEnumerable<int> {

    IEnumerable<int> CreateEnumerable() {
        yield return 123;
        yield return 456;
        for (int i = 0; i < 6; i++) {
            yield return i;
        }//for
    }//method

    public IEnumerator<int> GetEnumerator() {
        return CreateEnumerable().GetEnumerator();
    }//method

    IEnumerator IEnumerable.GetEnumerator() {
        return CreateEnumerable().GetEnumerator();
    }//method

}//class