HTML form submit to PHP script

It appears that in PHP you are obtaining the value of the submit button, not the select input. If you are using GET you will want to use $_GET['website_string'] or POST would be $_POST['website_string'].

You will probably want the following HTML:

<select name="website_string">
  <option value="" selected="selected"></option>
  <option value="abc">ABC</option>
  <option value="def">def</option>
  <option value="hij">hij</option>   
</select>
<input type="submit" />

With some PHP that looks like this:

<?php

$website_string = $_POST['website_string']; // or $_GET['website_string'];

?>

Try this:

<form method="post" action="check.php">
    <select name="website_string">
        <option value="" selected="selected"></option>
        <option VALUE="abc"> ABC</option>
        <option VALUE="def"> def</option>
        <option VALUE="hij"> hij</option>
    </select>
    <input TYPE="submit" name="submit" />
</form>

Both your select control and your submit button had the same name attribute, so the last one used was the submit button when you clicked it. All other syntax errors aside.

check.php

<?php
    echo $_POST['website_string'];
?>

Obligatory disclaimer about using raw $_POST data. Sanitize anything you'll actually be using in application logic.


<form method="POST" action="chk_kw.php">
    <select name="website_string"> 
        <option selected="selected"></option>
        <option value="abc">abc</option>
        <option value="def">def</option>
        <option value="hij">hij</option>   
    </select>
    <input type="submit">
</form>


  • As your form gets more complex, you can a quick check at top of your php script using print_r($_POST);, it'll show what's being submitted an the respective element name.
  • To get the submitted value of the element in question do:

    $website_string = $_POST['website_string'];

Tags:

Html

Php

Forms

Post