using ajax in php code example
Example 1: ajax jquery php
<!doctype html>
<html>
<head>
<script src="https://code.jquery.com/jquery-3.3.1.js" integrity="sha256-2Kok7MbOyxpgUVvAk/HJ2jigOSYS2auK4Pfzbm7uH60=" crossorigin="anonymous"></script>
</head>
<body>
<form id="loginform" method="post">
<div>
Username:
<input type="text" name="username" id="username" />
Password:
<input type="password" name="password" id="password" />
<input type="submit" name="loginBtn" id="loginBtn" value="Login" />
</div>
</form>
<script type="text/javascript">
$(document).ready(function() {
$('#loginform').submit(function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: 'login.php',
data: $(this).serialize(),
success: function(response)
{
var jsonData = JSON.parse(response);
if (jsonData.success == "1")
{
location.href = 'my_profile.php';
}
else
{
alert('Invalid Credentials!');
}
}
});
});
});
</script>
</body>
</html>
Example 2: ajax to php call
//Use $.ajax to call a server context (or URL, or whatever) to invoke a particular 'action'. What you want is something like:
$.ajax({ url: '/my/site',
data: {action: 'test'},
type: 'post',
success: function(output) {
alert(output);
}
});
//On the server side, the action POST parameter should be read and the corresponding value should point to the method to invoke, e.g.:
if(isset($_POST['action']) && !empty($_POST['action'])) {
$action = $_POST['action'];
switch($action) {
case 'test' : test();break;
case 'blah' : blah();break;
// ...etc...
}
}
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