"In" operator for numpy arrays?
You could compare the input arrays for equality
, which will perform broadcasted
comparisons across all elements in a
at each position in the last two axes against elements at corresponding positions in the second array. This will result in a boolean array of matches, in which we check for ALL
matches across the last two axes and finally check for ANY
match, like so -
((a==b).all(axis=(1,2))).any()
Sample run
1) Inputs :
In [68]: a
Out[68]:
array([[[2, 3, 0],
[1, 0, 1]],
[[3, 2, 0],
[0, 1, 1]],
[[2, 2, 0],
[1, 1, 1]],
[[1, 3, 0],
[2, 0, 1]],
[[3, 1, 0],
[0, 2, 1]]])
In [69]: b
Out[69]:
array([[3, 2, 0],
[0, 1, 1]])
2) Broadcasted elementwise comparisons :
In [70]: a==b
Out[70]:
array([[[False, False, True],
[False, False, True]],
[[ True, True, True],
[ True, True, True]],
[[False, True, True],
[False, True, True]],
[[False, False, True],
[False, False, True]],
[[ True, False, True],
[ True, False, True]]], dtype=bool)
3) ALL
match across last two axes and finally ANY
match :
In [71]: (a==b).all(axis=(1,2))
Out[71]: array([False, True, False, False, False], dtype=bool)
In [72]: ((a==b).all(axis=(1,2))).any()
Out[72]: True
Following similar steps for c
in a
-
In [73]: c
Out[73]:
array([[300, 200, 0],
[ 0, 100, 100]])
In [74]: ((a==c).all(axis=(1,2))).any()
Out[74]: False