In Rails, display time between two dates in English

The other answers may not give the type of output that you're looking for, because instead of giving a string of years, months, etc., the Rails helpers just show the largest unit. If you're looking for something more broken down, here's another option. Stick this method into a helper:

def time_diff_in_natural_language(from_time, to_time)
  from_time = from_time.to_time if from_time.respond_to?(:to_time)
  to_time = to_time.to_time if to_time.respond_to?(:to_time)
  distance_in_seconds = ((to_time - from_time).abs).round
  components = []

  %w(year month week day).each do |interval|
    # For each interval type, if the amount of time remaining is greater than
    # one unit, calculate how many units fit into the remaining time.
    if distance_in_seconds >= 1.send(interval)
      delta = (distance_in_seconds / 1.send(interval)).floor
      distance_in_seconds -= delta.send(interval)
      components << pluralize(delta, interval)
      # if above line give pain. try below one  
      # components <<  interval.pluralize(delta)  
    end
  end

  components.join(", ")
end

And then in a view you can say something like:

<%= time_diff_in_natural_language(Time.now, 2.5.years.ago) %>
=> 2 years, 6 months, 2 days 

The given method only goes down to days, but can be easily extended to add in smaller units if desired.

The Rails' ActionView module includes two methods that may do what you require:

• distance_of_time_in_words
• distance_of_time_in_words_to_now

I tried Daniel's solution and found some incorrect results for a few test cases, due to the fact that it doesn't correctly handle the variable number of days found in months:

> 30.days < 1.month
   => false

So, for example:

> d1 = DateTime.civil(2011,4,4)
> d2 = d1 + 1.year + 5.months
> time_diff_in_natural_language(d1,d2)
=> "1 year, 5 months, 3 days" 

The following will give you the correct number of {years,months,days,hours,minutes,seconds}:

def time_diff(from_time, to_time)
  %w(year month day hour minute second).map do |interval|
    distance_in_seconds = (to_time.to_i - from_time.to_i).round(1)
    delta = (distance_in_seconds / 1.send(interval)).floor
    delta -= 1 if from_time + delta.send(interval) > to_time
    from_time += delta.send(interval)
    delta
  end
end
> time_diff(d1,d2)
 => [1, 5, 0, 0, 0, 0]