Increment a value in XSLT
XSLT is a functional language and among other things this means that variables in XSLT are immutable and once they have been defined their value cannot be changed.
Here is how the same effect can be achieved in XSLT:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<posts>
<xsl:for-each select="data/posts/entry">
<xsl:variable name="i" select="position()" />
<xsl:copy>
<xsl:value-of select="concat('$i = ', $i)"/>
</xsl:copy>
</xsl:for-each>
</posts>
</xsl:template>
</xsl:stylesheet>
when this transformation is applied on the following XML document:
<data>
<posts>
<entry/>
<entry/>
<entry/>
<entry/>
<entry/>
</posts>
</data>
the result is:
<posts>
<entry>$i = 1</entry>
<entry>$i = 2</entry>
<entry>$i = 3</entry>
<entry>$i = 4</entry>
<entry>$i = 5</entry>
</posts>
You can use the position()
function:
- Example 1
- Example 2
<xsl:for-each select="data/posts/entry">
<xsl:text>
Postion: '
</xsl:text>
<xsl:value-of select = "position()" />
<xsl:text>
'
</xsl:text>
<!-- DO SOMETHING -->
</xsl:for-each>
I ran into that myself two years ago. You need to do use recursion for this. I forget the exact syntax, but this site might help:
Tip: Loop with recursion in XSLT
The strategy works basically as follows: Replace for
loop with a template "method". Have it recieve a parameter i
. Do the body of the for
loop in the template method. If i > 0
call the template method again (recursion) with i - 1
as parameter.
Pseudocode:
for i = 0 to 10:
print i
becomes:
def printer(i):
print i
if i < 10:
printer(i + 1)
printer(0)
Please note that using position()
in a xsl:for-each
(see other answers) can be simpler if all you want to do is have a variable increment. Use the kind of recursion explained here if you want a more complicated loop / condition.