Android ViewPager get the current View
I use this method with android.support.v4.view.ViewPager
View getCurrentView(ViewPager viewPager) {
try {
final int currentItem = viewPager.getCurrentItem();
for (int i = 0; i < viewPager.getChildCount(); i++) {
final View child = viewPager.getChildAt(i);
final ViewPager.LayoutParams layoutParams = (ViewPager.LayoutParams) child.getLayoutParams();
Field f = layoutParams.getClass().getDeclaredField("position"); //NoSuchFieldException
f.setAccessible(true);
int position = (Integer) f.get(layoutParams); //IllegalAccessException
if (!layoutParams.isDecor && currentItem == position) {
return child;
}
}
} catch (NoSuchFieldException e) {
Log.e(TAG, e.toString());
} catch (IllegalArgumentException e) {
Log.e(TAG, e.toString());
} catch (IllegalAccessException e) {
Log.e(TAG, e.toString());
}
return null;
}
I've figured it out. What I did was to call setTag()
with a name to all View
s/ListView
s, and just call findViewWithTag(mytag)
, mytag
being the tag.
Unfortunately, there's no other way to solve this.
I just came across the same issue and resolved it by using:
View view = MyActivity.mViewPager.getFocusedChild();