attribute error: list object has not attribute lstrip in sending an email with attachment

it was a small error. receiver parameter was list type. either it should be list converted to string using join method or if it is a single recipient, then pass it as a string only

receiver = ['[email protected]'] This is a list but msg['To'] is expecting a string and hence the error.

You can use ','.join(receiver) and that should solve your problem.

This appears to be a issue from smtplib. The documentation clearly says that it accepts a list

The arguments are:
        - from_addr    : The address sending this mail.
        - **to_addrs     : A list of addresses to send this mail to.  A bare
                         string will be treated as a list with 1 address.**
        - msg          : The message to send.

Usage from documentation:

 "Example:

     >>> import smtplib
     >>> s=smtplib.SMTP("localhost")
     **>>> tolist= 
     ["[email protected]","[email protected]","[email protected]","[email protected]"]**
     >>> msg = '''\\
     ... From: [email protected]
     ... Subject: testin'...
     ...
     ... This is a test '''
     >>> s.sendmail("[email protected]",tolist,msg)"

Also as said in the documentation if recipients are passed as string, mail is being sent to first mailid only.

So actually the problem is that SMTP.sendmail and email.MIMEText need two different things.

email.MIMEText sets up the "To:" header for the body of the e-mail. It is ONLY used for displaying a result to the human being at the other end, and like all e-mail headers, must be a single string. (Note that it does not actually have to have anything to do with the people who actually receive the message.)

SMTP.sendmail, on the other hand, sets up the "envelope" of the message for the SMTP protocol. It needs a Python list of strings, each of which has a single address.

So, what you need to do is COMBINE the two replies you received. Set msg['To'] to a single string, but pass the raw list to sendmail:

emails = ['a.com','b.com', 'c.com']** **msg['To'] = ', '.join( emails ) .... s.sendmail( msg['From'], emails, msg.as_string() )****