Bash regex =~ operator
-
What is the operator
=~
called?I'm not sure it has a name. The bash documentation just calls it the
=~
operator. -
Is it only used to compare the right side against the left side?
The right side is considered an extended regular expression. If the left side matches, the operator returns
0
, and1
otherwise. -
Why are double square brackets required when running a test?
Because
=~
is an operator of the[[ expression ]]
compound command.
The =~
operator is a regular expression match operator. This operator is inspired by Perl's use of the same operator for regular expression matching.
The [[ ]]
is treated specially by bash; consider that an augmented version of [ ]
construct:
[ ]
is actually a shell built-in command, which, can actually be implemented as an external command. Look at your /usr/bin, there is most likely a program called "[" there! Strictly speaking,[ ]
is not part of bash syntax.[[ ]]
is a shell keyword, which means it is part of shell syntax. Inside this construct, some reserved characters change meaning. For example,( )
means parenthesis like other programming language (not launching a subshell to execute what's inside the parentheses). Another example is that<
and>
means less than and greater than, not shell redirection. This allow more "natural" appearance of logical expressions, but it can be confusing for novice bash programmers.
Wirawan