Bash script: Using "script" command from a bash script for logging a session
Your shell script did not terminate. It is still running. You are getting a prompt because script
is spawning a new shell. the prompt you see is the prompt from the spawned shell.
The normal use case for script
is something like this:
- start
script
. this spawns a new shell. - do commands in the new shell.
- exit the shell and drop to previous shell
- examine the logfile created by
script
So basically script
is working as expected. You will have to find another way to achieve what you want.
You can log the execution of your script like this:
#! /bin/bash
exec > logfile 2>&1
set -x
FOO=BAR
echo $FOO
Explanation:
exec > logfile 2>&1
redirects stdout and stderr to logfileset -x
makes bash print every command before executing it
Example:
$ ./foo.sh
# (no output here because everything goes to logfile)
$ cat logfile
+ FOO=BAR
+ echo BAR
BAR
Disadvantage of this method is that the script prints no output for humans to see. Everything goes to the logfile.
Alternatively you can do it like this:
#! /bin/bash
# nothing special here
FOO=BAR
echo $FOO
Then execute like this:
$ script -c "bash -x foo.sh"
Script started, file is typescript
+ FOO=BAR
+ echo BAR
BAR
Script done, file is typescript
now output is directly visible and also saved to logfile (default name of logfile is typescript
)
$ cat typescript
Script started on Mi 18 Mai 2011 01:05:29 CEST
+ FOO=BAR
+ echo BAR
BAR
Script done on Mi 18 Mai 2011 01:05:29 CEST
Your bash script is still running, but it has spawned a new interactive shell. The bash script is waiting for script
to complete, which will only happen when the interactive shell is terminated (either by being killed, or by the user typing exit
).
To make the command after script
be logged by script
, do it like this:
script build_log -c 'echo -e "* This line should appear inside the /"build_log/" log file..."'
However, script
will stop running after running that command.
To run multiple commands inside script
, put those commands inside another bash script and specify that bash script as the command to run to the -c
option.