C++11 emplace_back on vector<struct>?

You need to explicitly define a ctor for the class:

#include <string>
#include <vector>

using namespace std;

struct T
{
    int a;
    double b;
    string c;

    T(int a, double b, string &&c) 
        : a(a)
        , b(b)
        , c(std::move(c)) 
    {}
};

vector<T> V;

int main()
{
    V.emplace_back(42, 3.14, "foo");
}

The point of using emplace_back is to avoid creating a temporary object, which is then copied (or moved) to the destination. While it is also possible to create a temporary object, then pass that to emplace_back, it defeats (at least most of) the purpose. What you want to do is pass individual arguments, then let emplace_back invoke the ctor with those arguments to create the object in place.

Of course, this is not an answer, but it shows an interesting feature of tuples:

#include <string>
#include <tuple>
#include <vector>

using namespace std;

using T = tuple <
    int,
    double,
    string
>;

vector<T> V;

int main()
{
    V.emplace_back(42, 3.14, "foo");
}

For anyone from the future, this behavior will be changed in C++20.

In other words, even though implementation internally will still call T(arg0, arg1, ...) it will be considered as regular T{arg0, arg1, ...} that you would expect.