C# flattening json structure
JObject jsonObject=JObject.Parse(theJsonString);
IEnumerable<JToken> jTokens = jsonObject.Descendants().Where(p => p.Count() == 0);
Dictionary<string, string> results = jTokens.Aggregate(new Dictionary<string, string>(), (properties, jToken) =>
{
properties.Add(jToken.Path, jToken.ToString());
return properties;
});
I had the same requirement of flattening a nested json structure to a dictionary object. Found the solution here.
You can use https://github.com/jsonfx/jsonfx to deserialize json into a dynamic object. Then use the ExpandoObject to get what you want.
public Class1()
{
string json = @"{
""name"": ""test"",
""father"": {
""name"": ""test2"",
""age"": 13,
""dog"": {
""color"": ""brown""
}
}
}";
var reader = new JsonFx.Json.JsonReader();
dynamic output = reader.Read(json);
Dictionary<string, object> dict = new Dictionary<string, object>();
GenerateDictionary((System.Dynamic.ExpandoObject) output, dict, "");
}
private void GenerateDictionary(System.Dynamic.ExpandoObject output, Dictionary<string, object> dict, string parent)
{
foreach (var v in output)
{
string key = parent + v.Key;
object o = v.Value;
if (o.GetType() == typeof(System.Dynamic.ExpandoObject))
{
GenerateDictionary((System.Dynamic.ExpandoObject)o, dict, key + ".");
}
else
{
if (!dict.ContainsKey(key))
{
dict.Add(key, o);
}
}
}
}
As of .NET Core 3.0 JsonDocument
is a way (Json.NET is not needed). I'm sure this will get easier.
using System.Linq;
using System.Text.Json;
(...)
public static Dictionary<string, JsonElement> GetFlat(string json)
{
IEnumerable<(string Path, JsonProperty P)> GetLeaves(string path, JsonProperty p)
=> p.Value.ValueKind != JsonValueKind.Object
? new[] { (Path: path == null ? p.Name : path + "." + p.Name, p) }
: p.Value.EnumerateObject() .SelectMany(child => GetLeaves(path == null ? p.Name : path + "." + p.Name, child));
using (JsonDocument document = JsonDocument.Parse(json)) // Optional JsonDocumentOptions options
return document.RootElement.EnumerateObject()
.SelectMany(p => GetLeaves(null, p))
.ToDictionary(k => k.Path, v => v.P.Value.Clone()); //Clone so that we can use the values outside of using
}
A more expressive version is shown below.
Test
using System.Linq;
using System.Text.Json;
(...)
var json = @"{
""name"": ""test"",
""father"": {
""name"": ""test2"",
""age"": 13,
""dog"": {
""color"": ""brown""
}
}
}";
var d = GetFlat(json);
var options2 = new JsonSerializerOptions { WriteIndented = true };
Console.WriteLine(JsonSerializer.Serialize(d, options2));
Output
{
"name": "test",
"father.name": "test2",
"father.age": 13,
"father.dog.color": "brown"
}
More expressive version
using System.Linq;
using System.Text.Json;
(...)
static Dictionary<string, JsonElement> GetFlat(string json)
{
using (JsonDocument document = JsonDocument.Parse(json))
{
return document.RootElement.EnumerateObject()
.SelectMany(p => GetLeaves(null, p))
.ToDictionary(k => k.Path, v => v.P.Value.Clone()); //Clone so that we can use the values outside of using
}
}
static IEnumerable<(string Path, JsonProperty P)> GetLeaves(string path, JsonProperty p)
{
path = (path == null) ? p.Name : path + "." + p.Name;
if (p.Value.ValueKind != JsonValueKind.Object)
yield return (Path: path, P: p);
else
foreach (JsonProperty child in p.Value.EnumerateObject())
foreach (var leaf in GetLeaves(path, child))
yield return leaf;
}