Cannot use a CONTAINS or FREETEXT predicate on table or indexed view because it is not full-text indexed
Make sure you have full-text search feature installed.
Create full-text search catalog.
use AdventureWorks create fulltext catalog FullTextCatalog as default select * from sys.fulltext_catalogs
Create full-text search index.
create fulltext index on Production.ProductDescription(Description) key index PK_ProductDescription_ProductDescriptionID
Before you create the index, make sure:
- you don't already have full-text search index on the table as only one full-text search index allowed on a table
- a unique index exists on the table. The index must be based on single-key column, that does not allow NULL.
- full-text catalog exists. You have to specify full-text catalog name explicitly if there is no default full-text catalog.
You can do step 2 and 3 in SQL Sever Management Studio. In object explorer, right click on a table, select Full-Text index
menu item and then Define Full-Text Index...
sub-menu item. Full-Text indexing wizard will guide you through the process. It will also create a full-text search catalog for you if you don't have any yet.
You can find more info at MSDN
A workaround for CONTAINS
: If you don't want to create a full text Index on the column, and performance is not one of your priorities you could use the LIKE
statement which doesn't need any prior configuration:
Example: find all Products that contains the letter Q:
SELECT ID, ProductName
FROM [ProductsDB].[dbo].[Products]
WHERE [ProductsDB].[dbo].[Products].ProductName LIKE '%Q%'
You must define Full-Text-Index
on all tables in database where you require to use a query with CONTAINS
which will take sometime.
Instead you can use the LIKE
which will give you instant results without the need to adjust any settings for the tables.
Example:
SELECT * FROM ChartOfAccounts WHERE AccountName LIKE '%Tax%'
The same result obtained with CONTAINS
can be obtained with LIKE
.
see the result: