Colour output of program run under BASH
Most terminals respect the ASCII color sequences. They work by outputting ESC
, followed by [
, then a semicolon-separated list of color values, then m
. These are common values:
Special
0 Reset all attributes
1 Bright
2 Dim
4 Underscore
5 Blink
7 Reverse
8 Hidden
Foreground colors
30 Black
31 Red
32 Green
33 Yellow
34 Blue
35 Magenta
36 Cyan
37 White
Background colors
40 Black
41 Red
42 Green
43 Yellow
44 Blue
45 Magenta
46 Cyan
47 White
So outputting "\033[31;47m"
should make the terminal front (text) color red and the background color white.
You can wrap it nicely in a C++ form:
enum Color {
NONE = 0,
BLACK, RED, GREEN,
YELLOW, BLUE, MAGENTA,
CYAN, WHITE
}
std::string set_color(Color foreground = 0, Color background = 0) {
char num_s[3];
std::string s = "\033[";
if (!foreground && ! background) s += "0"; // reset colors if no params
if (foreground) {
itoa(29 + foreground, num_s, 10);
s += num_s;
if (background) s += ";";
}
if (background) {
itoa(39 + background, num_s, 10);
s += num_s;
}
return s + "m";
}
Here's a version of the code above from @nightcracker, using stringstream
instead of itoa
. (This runs using clang++, C++11, OS X 10.7, iTerm2, bash)
#include <iostream>
#include <string>
#include <sstream>
enum Color
{
NONE = 0,
BLACK, RED, GREEN,
YELLOW, BLUE, MAGENTA,
CYAN, WHITE
};
static std::string set_color(Color foreground = NONE, Color background = NONE)
{
std::stringstream s;
s << "\033[";
if (!foreground && ! background){
s << "0"; // reset colors if no params
}
if (foreground) {
s << 29 + foreground;
if (background) s << ";";
}
if (background) {
s << 39 + background;
}
s << "m";
return s.str();
}
int main(int agrc, char* argv[])
{
std::cout << "These words should be colored [ " <<
set_color(RED) << "red " <<
set_color(GREEN) << "green " <<
set_color(BLUE) << "blue" <<
set_color() << " ]" <<
std::endl;
return EXIT_SUCCESS;
}
You might want to look at VT100 control codes.