Converting a double to an int in C#

Because Convert.ToInt32 rounds:

Return Value: rounded to the nearest 32-bit signed integer. If value is halfway between two whole numbers, the even number is returned; that is, 4.5 is converted to 4, and 5.5 is converted to 6.

...while the cast truncates:

When you convert from a double or float value to an integral type, the value is truncated.

Update: See Jeppe Stig Nielsen's comment below for additional differences (which however do not come into play if score is a real number as is the case here).

Casting will ignore anything after the decimal point, so 8.6 becomes 8.

Convert.ToInt32(8.6) is the safe way to ensure your double gets rounded to the nearest integer, in this case 9.

you can round your double and cast ist:

(int)Math.Round(myDouble);