Converting a float to hh:mm format

Alternatively to using datetime, you can just use simple formatting with a bit of maths, eg:

result = '{0:02.0f}:{1:02.0f}'.format(*divmod(time * 60, 60))

(This assumes that time is nonnegative.)

Using datetime.timedelta:

>>> import datetime
>>> datetime.timedelta(hours=9.888888888888886)
datetime.timedelta(0, 35600)
>>> str(datetime.timedelta(hours=9.888888888888886))
'9:53:20'
>>> str(datetime.timedelta(hours=9.888888888888886)).rsplit(':', 1)[0]
'9:53'

---

>>> datetime.datetime.combine(datetime.date.today(), datetime.time()) + \
... datetime.timedelta(hours=9.888888888888886)
datetime.datetime(2014, 12, 16, 9, 53, 20)
>>> _.strftime('%H:%M')
'09:53'

Using divmod you get the remainder and the quotient of a division.

minutes = 9.888888888888886*60
hours, minutes = divmod(minutes, 60)

print "%02d:%02d"%(hours,minutes)

Output:

09:53

If you want the seconds too:

seconds = 9.888888888888886*60*60
minutes, seconds = divmod(seconds, 60)
hours, minutes = divmod(minutes, 60)

print "%02d:%02d:%02d"%(hours,minutes,seconds)