Converting string of 1s and 0s into binary value
#include <stdio.h>
#include <stdlib.h>
int main(void) {
char * ptr;
long parsed = strtol("11110111", & ptr, 2);
printf("%lX\n", parsed);
return EXIT_SUCCESS;
}
For larger numbers, there as a long long
version, strtoll
.
You can use strtol
char string[] = "1101110100110100100000";
char * end;
long int value = strtol (string,&end,2);
You can use std::bitset (if then length of your bits is known at compile time)
Though with some program you could break it up into chunks and combine.
#include <bitset>
#include <iostream>
int main()
{
std::bitset<5> x(std::string("01011"));
std::cout << x << ":" << x.to_ulong() << std::endl;
}