Creating a custom query with Spring DATA JPA?

Using EntityManager you can achieve this .

Suppose your entity class is like bellow:

import javax.persistence.*;
import java.math.BigDecimal;

@Entity
@Table(name = "USER_INFO_TEST")
public class UserInfoTest {
    private int id;
    private String name;
    private String rollNo;

    public UserInfoTest() {
    }

    public UserInfoTest(int id, String name) {
    this.id = id;
    this.name = name;
    }

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "ID", nullable = false, precision = 0)
    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    @Basic
    @Column(name = "name", nullable = true)
    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    @Basic
    @Column(name = "roll_no", nullable = true)
    public String getRollNo() {
        return rollNo;
    }

    public void setRollNo(String rollNo) {
        this.rollNo = rollNo;
    }
}

And your query is "select id, name from users where roll_no = 1001".

Here query will return an object with id and a name column. Your Response class is like below:

Your Response class is like:

public class UserObject{
    int id;
    String name;
    String rollNo;

    public UserObject(Object[] columns) {
        this.id = (columns[0] != null)?((BigDecimal)columns[0]).intValue():0;
        this.name = (String) columns[1];
    }

    public int getId() {
        return id;
    }

    public void setId(int id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getRollNo() {
        return rollNo;
    }

    public void setRollNo(String rollNo) {
        this.rollNo = rollNo;
    }
}

here UserObject constructor will get an Object Array and set data with the object.

public UserObject(Object[] columns) {
            this.id = (columns[0] != null)?((BigDecimal)columns[0]).intValue():0;
            this.name = (String) columns[1];
        }

Your query executing function is like bellow :

public UserObject getUserByRoll(EntityManager entityManager,String rollNo) {

        String queryStr = "select id,name from users where roll_no = ?1";
        try {
            Query query = entityManager.createNativeQuery(queryStr);
            query.setParameter(1, rollNo);

            return new UserObject((Object[]) query.getSingleResult());
        } catch (Exception e) {
            e.printStackTrace();
            throw e;
        }
    }

Here you have to import bellow packages:

import javax.persistence.Query;
import javax.persistence.EntityManager;

Now your main class, you have to call this function. First get EntityManager and call this getUserByRoll(EntityManager entityManager,String rollNo) function. Calling procedure is given below:

Here is the Imports

import javax.persistence.EntityManager;
import javax.persistence.PersistenceContext;

get EntityManager from this way:

@PersistenceContext
private EntityManager entityManager;

UserObject userObject = getUserByRoll(entityManager,"1001");

Now you have data in this userObject.

Note:

query.getSingleResult() return a object array. You have to maintain the column position and data type with query column position.

select id,name from users where roll_no = 1001

query return a array and it's [0] --> id and 1 -> name.

More info visit this thread .

The only part of it you can parameterise are values used in WHERE clause. Consider this sample from official doc:

public interface UserRepository extends JpaRepository<User, Long> {
  @Query(value = "SELECT * FROM USERS WHERE EMAIL_ADDRESS = ?1", nativeQuery = true)
  User findByEmailAddress(String emailAddress);
}

There is no special support for this. But what you can do is create a custom method with a String parameter and in your implementation get the EntityManager injected and execute it.

Possibly helpful links:

https://docs.spring.io/spring-data/jpa/docs/current/reference/html/#repositories.custom-implementations

How to access entity manager with spring boot and spring data

Note: I would reconsider if what you are trying to do is a good idea because it bleeds implementation details of the repository into the rest of the application.