cropping an area from BitmapData with C#
I whipped up a quick (and admittedly rough) manual solution that demonstrates how to do this using locked bitmaps. It should be considerably faster than the alternative methods, but does involve a lot more code.
Bitmap bmp = new Bitmap(@"C:\original.jpg");
Rectangle rect = new Rectangle(0, 0, bmp.Width, bmp.Height);
BitmapData rawOriginal = bmp.LockBits(new Rectangle(0, 0, bmp.Width, bmp.Height), ImageLockMode.ReadOnly, PixelFormat.Format32bppArgb);
int origByteCount = rawOriginal.Stride * rawOriginal.Height;
byte[] origBytes = new Byte[origByteCount];
Marshal.Copy(rawOriginal.Scan0, origBytes, 0, origByteCount);
//I want to crop a 100x100 section starting at 15, 15.
int startX = 15;
int startY = 15;
int width = 100;
int height = 100;
int BPP = 4; //4 Bpp = 32 bits, 3 = 24, etc.
byte[] croppedBytes = new Byte[width * height * BPP];
//Iterate the selected area of the original image, and the full area of the new image
for (int i = 0; i < height; i++)
{
for (int j = 0; j < width * BPP; j += BPP)
{
int origIndex = (startX * rawOriginal.Stride) + (i * rawOriginal.Stride) + (startY * BPP) + (j);
int croppedIndex = (i * width * BPP) + (j);
//copy data: once for each channel
for (int k = 0; k < BPP; k++)
{
croppedBytes[croppedIndex + k] = origBytes[origIndex + k];
}
}
}
//copy new data into a bitmap
Bitmap croppedBitmap = new Bitmap(width, height);
BitmapData croppedData = croppedBitmap.LockBits(new Rectangle(0, 0, width, height), ImageLockMode.WriteOnly, PixelFormat.Format32bppArgb);
Marshal.Copy(croppedBytes, 0, croppedData.Scan0, croppedBytes.Length);
bmp.UnlockBits(rawOriginal);
croppedBitmap.UnlockBits(croppedData);
croppedBitmap.Save(@"C:\test.bmp");
I used this original image:
To output this image, cropped to 100x100 @ 15,15:
Obviously if you use this code, you'll want to clean it up a bit and add error handling. If I understand your question correctly, doing things this way should eliminate the need to use AForge at all.
Fopedush's answer benefits greatly when we subsitute Marshal.copy with memcpy, because that way we don't have to copy it through a byte[] array. That way the memory gets copied only once, instead of three times!
[DllImport("msvcrt.dll", CallingConvention = CallingConvention.Cdecl)]
static unsafe extern int memcpy(byte* dest, byte* src, long count);
static public Bitmap cropBitmap(Bitmap sourceImage, Rectangle rectangle)
{
const int BPP = 4; //4 Bpp = 32 bits; argb
var sourceBitmapdata = sourceImage.LockBits(rectangle, ImageLockMode.ReadOnly, PixelFormat.Format32bppArgb);
var croppedImage = new Bitmap(rectangle.Width, rectangle.Height, PixelFormat.Format32bppArgb);
var croppedBitmapData = croppedImage.LockBits(new Rectangle(0, 0, rectangle.Width, rectangle.Height), ImageLockMode.WriteOnly, PixelFormat.Format32bppArgb);
unsafe
{
croppedBitmapData.Stride = sourceBitmapdata.Stride;
byte* sourceImagePointer = (byte*)sourceBitmapdata.Scan0.ToPointer();
byte* croppedImagePointer = (byte*)croppedBitmapData.Scan0.ToPointer();
memcpy(croppedImagePointer, sourceImagePointer,
Math.Abs(croppedBitmapData.Stride) * rectangle.Height);
}
sourceImage.UnlockBits(sourceBitmapdata);
croppedImage.UnlockBits(croppedBitmapData);
return croppedImage;
}
My results are:
BitmapClone: 1823 ms
LockBits: 4857 ms
Rectangle: 1479 ms
My method: 559 ms
My method with LockBits on source image done only once (before loop): 160 ms
I don't have AForge so I haven't included that, but by looking on op's results it would be slower than this. I was testing cropping the image in half.
Please note, that if we would exchange memcpy with:
for (int k = 0; k < Math.Abs(croppedBitmapData.Stride) * rectangle.Height; k++)
*(croppedImagePointer++) = *(sourceImagePointer++);
it gets 10x slower!
You can try something like this:
public static Bitmap CropBitmap(Bitmap bitmap, int x, int y, int w, int h)
{
Rectangle rect = new Rectangle(x, y, w, h);
Bitmap cropped = bitmap.Clone(rect, bitmap.PixelFormat);
return cropped;
}
And do something like this in yout code (sample):
var croppedImagem = CropBitmap(dataOriginal, 0, 0, 100, 100);
I hope it helps!