Delete files older than 10 days using shell script in Unix
Just spicing up the shell script above to delete older files but with logging and calculation of elapsed time
#!/bin/bash
path="/data/backuplog/"
timestamp=$(date +%Y%m%d_%H%M%S)
filename=log_$timestamp.txt
log=$path$filename
days=7
START_TIME=$(date +%s)
find $path -maxdepth 1 -name "*.txt" -type f -mtime +$days -print -delete >> $log
echo "Backup:: Script Start -- $(date +%Y%m%d_%H%M)" >> $log
... code for backup ...or any other operation .... >> $log
END_TIME=$(date +%s)
ELAPSED_TIME=$(( $END_TIME - $START_TIME ))
echo "Backup :: Script End -- $(date +%Y%m%d_%H%M)" >> $log
echo "Elapsed Time :: $(date -d 00:00:$ELAPSED_TIME +%Hh:%Mm:%Ss) " >> $log
The code adds a few things.
- log files named with a timestamp
- log folder specified
- find looks for *.txt files only in the log folder
- type f ensures you only deletes files
- maxdepth 1 ensures you dont enter subfolders
- log files older than 7 days are deleted ( assuming this is for a backup log)
- notes the start / end time
- calculates the elapsed time for the backup operation...
Note: to test the code, just use -print instead of -print -delete. But do check your path carefully though.
Note: Do ensure your server time is set correctly via date - setup timezone/ntp correctly . Additionally check file times with 'stat filename'
Note: mtime can be replaced with mmin for better control as mtime discards all fractions (older than 2 days (+2 days) actually means 3 days ) when it deals with getting the timestamps of files in the context of days
-mtime +$days ---> -mmin +$((60*24*$days))
If you can afford working via the file data, you can do
find -mmin +14400 -delete
find
is the common tool for this kind of task :
find ./my_dir -mtime +10 -type f -delete
EXPLANATIONS
./my_dir
your directory (replace with your own)-mtime +10
older than 10 days-type f
only files-delete
no surprise. Remove it to test yourfind
filter before executing the whole command
And take care that ./my_dir
exists to avoid bad surprises !