Deleting files which start with a name Python

import os, glob
for filename in glob.glob("mypath/version*"):
    os.remove(filename) 

Substitute the correct path (or . (= current directory)) for mypath. And make sure you don't get the path wrong :)

This will raise an Exception if a file is currently in use.

import os
os.chdir("/home/path")
for file in os.listdir("."):
    if os.path.isfile(file) and file.startswith("version"):
         try:
              os.remove(file)
         except Exception,e:
              print e

In which language?

In bash (Linux / Unix) you could use:

rm version*

or in batch (Windows / DOS) you could use:

del version*

If you want to write something to do this in Python it would be fairly easy - just look at the documentation for regular expressions.

edit: just for reference, this is how to do it in Perl:

opendir (folder, "./") || die ("Cannot open directory!");
@files = readdir (folder);
closedir (folder);

unlink foreach (grep /^version/, @files);

If you really want to use Python, you can just use a combination of os.listdir(), which returns a listing of all the files in a certain directory, and os.remove().

I.e.:

my_dir = # enter the dir name
for fname in os.listdir(my_dir):
    if fname.startswith("version"):
        os.remove(os.path.join(my_dir, fname))

However, as other answers pointed out, you really don't have to use Python for this, the shell probably natively supports such an operation.