Destructuring object and ignore one of the results

You could use Object Rest Spread operator magic.

const props = { a: 1, b: 2, c: 3 };
const { a, ...propsNoA } = props;
console.log(propsNoA); // => { b: 2, c: 3 }

So in your case it would be:

const { styles, ...propsNoStyles } = this.props;
const section = cloneElement(this.props.children, {
  className: this.props.styles.section
  ...this.propsNoStyles,
});

You can use the object rest/spread syntax:

// We destructure our "this.props" creating a 'styles' variable and
// using the object rest syntax we put the rest of the properties available
// from "this.props" into a variable called 'otherProps' 
const { styles, ...otherProps } = this.props;
const section = cloneElement(this.props.children, {
  className: styles.section,
  // We spread our props, which excludes the 'styles'
  ...otherProps,
});

I assume that you already have support from this syntax based on your code above, but please be aware that this is a proposed syntax which is made available to you via the babel stage 1 preset. If you get syntax errors on execution you can install the preset as follows:

 npm install babel-preset-stage-1 --save-dev

And then add it to the presets section of your babel configuration. For example in your .babelrc file:

 "presets": [ "es2015", "react", "stage-1" ]

---

Update based on comment on question by OP.

Okay, so you say that you already have a styles variable declared before this block? We can manage this case too. You can rename your destructured arguments to avoid this.

For example:

const styles = { foo: 'bar' };

const { styles: otherStyles, ...otherProps } = this.props;
const section = cloneElement(this.props.children, {
  className: otherStyles.section,
  // We spread our props, which excludes the 'styles'
  ...otherProps,
});