Django select max id

I know this already has a right answer but here it's another way of doing it:

prev = Image.objects.last()

This gives you the last object.

Just order by reverse id, and take the top one.

Image.objects.all().order_by("-id")[0]

In current version of django (1.4) it is even more readable

Image.objects.latest('id').id

Your logic is right, this will return the max id

res = Image.objects.filter().aggregate(max_id=Max('pk'))
res.get('max_id')