Django | sort dict in template

create a custom filter, which is like this:

from django import template
from django.utils.datastructures import SortedDict

register = template.Library()

@register.filter(name='sort')
def listsort(value):
    if isinstance(value, dict):
        new_dict = SortedDict()
        key_list = sorted(value.keys())
        for key in key_list:
            new_dict[key] = value[key]
        return new_dict
    elif isinstance(value, list):
        return sorted(value)
    else:
        return value
    listsort.is_safe = True

then in your template you shall call it using:

{% for key, value in companies.items|sort %}
      {{ key }} {{ value }}
{% endfor %}

You will be able to get the sorted dict by Key.

a custom template filter will do the trick.

from django import template
register = template.Library()

def dict_get(value, arg):
    #custom template tag used like so:
    #{{dictionary|dict_get:var}}
    #where dictionary is duh a dictionary and var is a variable representing
    #one of it's keys

    return value[arg]

register.filter('dict_get',dict_get)

more on custom template filters: http://docs.djangoproject.com/en/dev/howto/custom-template-tags/#howto-custom-template-tags

in your example you'd do:

{% for employee, dependents in company_dict|company %}