Doctrine: Counting an entity's items with a condition

Well, you could use the QueryBuilder to setup a COUNT query:

Presuming that $dm is your entity manager.

$qb = $dm->createQueryBuilder();

$qb->select($qb->expr()->count('u'))
   ->from('User', 'u')
   ->where('u.type = ?1')
   ->setParameter(1, 'employee');

$query = $qb->getQuery();

$usersCount = $query->getSingleScalarResult();

Or you could just write it in DQL:

$query = $dm->createQuery("SELECT COUNT(u) FROM User u WHERE u.type = ?1");
$query->setParameter(1, 'employee');

$usersCount = $query->getSingleScalarResult();

The counts might need to be on the id field, rather than the object, can't recall. If so just change the COUNT(u) or ->count('u') to COUNT(u.id) or ->count('u.id') or whatever your primary key field is called.

This question is 3 years old but there is a way to keep the simplicity of the findBy() for count with criteria.

On your repository you can add this method :

    public function countBy(array $criteria)
    {
        $persister = $this->_em->getUnitOfWork()->getEntityPersister($this->_entityName);
        return $persister->count($criteria);
    }

So your code will looks like this :

$criteria = ['type' => 'employee'];
$users = $repository->findBy($criteria, ['name' => 'ASC'], 0, 20);
$nbUsers = $repository->countBy($criteria);

Since doctrine 2.6 you can just count the result of the provided conditions when you don't really need the data:

$usersCount = $dm->getRepository('User')->count(array('type' => 'employee'));

Upgrade to 2.6