Exclude route from express middleware
Even though there is no build-in middleware filter system in expressjs, you can achieve this in at least two ways.
First method is to mount all middlewares that you want to skip to a regular expression path than includes a negative lookup:
// Skip all middleware except rateLimiter and proxy when route is /example_route
app.use(/\/((?!example_route).)*/, app_lookup);
app.use(/\/((?!example_route).)*/, timestamp_validator);
app.use(/\/((?!example_route).)*/, request_body);
app.use(/\/((?!example_route).)*/, checksum_validator);
app.use(rateLimiter);
app.use(/\/((?!example_route).)*/, whitelist);
app.use(proxy);
Second method, probably more readable and cleaner one, is to wrap your middleware with a small helper function:
var unless = function(path, middleware) {
return function(req, res, next) {
if (path === req.path) {
return next();
} else {
return middleware(req, res, next);
}
};
};
app.use(unless('/example_route', app_lookup));
app.use(unless('/example_route', timestamp_validator));
app.use(unless('/example_route', request_body));
app.use(unless('/example_route', checksum_validator));
app.use(rateLimiter);
app.use(unless('/example_route', whitelist));
app.use(proxy);
If you need more powerfull route matching than simple path === req.path
you can use path-to-regexp module that is used internally by Express.
UPDATE :- In express 4.17
req.path
returns only '/', so use req.baseUrl
:
var unless = function(path, middleware) {
return function(req, res, next) {
if (path === req.baseUrl) {
return next();
} else {
return middleware(req, res, next);
}
};
};
Built upon the answer from @lukaszfiszer as I wanted more than one route excluded. You can add as many as you want here.
var unless = function(middleware, ...paths) {
return function(req, res, next) {
const pathCheck = paths.some(path => path === req.path);
pathCheck ? next() : middleware(req, res, next);
};
};
app.use(unless(redirectPage, "/user/login", "/user/register"));
Can't add as comment sorry.