Extract substring according to regexp with sed or grep

Try this,

sed -nE 's/^pass2:.*<(.*)>.*$/\1/p'

Or POSIXly (-E has not made it to the POSIX standard yet as of 2019):

sed -n 's/^pass2:.*<\(.*\)>.*$/\1/p'

Output:

$ printf '%s\n' 'pass2: <Marvell Console 1.01> Removable Processor SCSI device' | sed -nE 's/^pass2:.*<(.*)>.*$/\1/p'
Marvell Console 1.01

This will only print the last occurrence of <...> for each line.

How about -o under grep to just print the matching part? We still need to remove the <>, though, but tr works there.

dmesg |egrep -o "<([a-zA-Z\.0-9 ]+)>" |tr -d "<>"
Marvell Console 1.01

I tried below 3 methods by using sed, awk and python

sed command

echo "pass2: <Marvell Console 1.01> Removable Processor SCSI device" | sed "s/.*<//g"|sed "s/>.*//g"

output

Marvell Console 1.01

awk command

echo "pass2: <Marvell Console 1.01> Removable Processor SCSI device" | awk -F "[<>]" '{print $2}'

output

Marvell Console 1.01

python

#!/usr/bin/python
import re
h=[]
k=open('l.txt','r')
l=k.readlines()
for i in l:
    o=i.split(' ')
    for i in o[1:4]:
        h.append(i)
print (" ".join(h)).replace('>','').replace('<','')

output

Marvell Console 1.01