Extracting directory name from an absolute path using sed or awk

dirname

kent$  dirname "/home/edwprod/abortive_visit/bin/abortive_proc_call.ksh"
/home/edwprod/abortive_visit/bin

sed

kent$  echo "/home/edwprod/abortive_visit/bin/abortive_proc_call.ksh"|sed 's#/[^/]*$##'
/home/edwprod/abortive_visit/bin

grep

kent$  echo "/home/edwprod/abortive_visit/bin/abortive_proc_call.ksh"|grep  -oP '^/.*(?=/)'
/home/edwprod/abortive_visit/bin

awk

kent$  echo "/home/edwprod/abortive_visit/bin/abortive_proc_call.ksh"|awk -F'/[^/]*$' '{print $1}'
/home/edwprod/abortive_visit/bin

May be command dirname is what you searching for?

dirname /home/edwprod/abortive_visit/bin/abortive_proc_call.ksh

Or if you want sed, so see my solution:

echo /home/edwprod/abortive_visit/bin/abortive_proc_call.ksh | sed 's/\(.*\)\/.*/\1/'

awk + for :

echo "/home/edwprod/abortive_visit/bin/abortive_proc_call.ksh" | awk 'BEGIN{res=""; FS="/";}{ for(i=2;i<=NF-1;i++) res=(res"/"$i);} END{print res}'

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