Find Duplicate Elements In Array Using Swift

Feeling ~clever~. Given an array of Ints

let x = [1, 1, 2, 3, 4, 5, 5]
let duplicates = Array(Set(x.filter({ (i: Int) in x.filter({ $0 == i }).count > 1})))
// [1, 5]

Please note, this is horrendously inefficient for everyone involved, including the compiler, and you.

I'm just showing off.

Edit: lol someone downvoted this, which leads me to reiterate, just in case: please DO NOT USE THIS in production or anywhere else.

Swift 4+

One liner, fast solution:

var numbers = [1,2,3,4,5,6,6,6,7,8,8]
let dups = Dictionary(grouping: numbers, by: {$0}).filter { $1.count > 1 }.keys

//Results: [6, 8]

To find duplicates, you could build cross reference by phone number, then filter that down to duplicates only. For example, consider:

let contacts = [
    Contact(name: "Rob",     phone: "555-1111"),
    Contact(name: "Richard", phone: "555-2222"),
    Contact(name: "Rachel",  phone: "555-1111"),
    Contact(name: "Loren",   phone: "555-2222"),
    Contact(name: "Mary",    phone: "555-3333"),
    Contact(name: "Susie",   phone: "555-2222")
]

You can build the cross reference dictionary with:

let crossReference = Dictionary(grouping: contacts, by: \.phone)

Then, to find the duplicates:

let duplicates = crossReference
    .filter { $1.count > 1 }

Clearly use whatever model types make sense for you, but the above uses the following Contact type:

struct Contact {
    let name: String
    let phone: String
}

There are many, many ways to implement this, so I would not focus on the implementation details above, but rather focus on the concept: Build cross reference original array by some key (e.g. phone number) and then filter results down to just those keys with duplicate values.

---

It sounds like you want to flatten this structure that reflects the duplicates, into a single array of contacts (I'm not sure why you'd want to do that, as you lose the structure identifying which are duplicates of each other), but if you want to do that, you can flatMap it:

let flattenedDuplicates = crossReference
    .filter { $1.count > 1 }                 // filter down to only those with multiple contacts
    .flatMap { $0.1 }                        // flatten it down to just array of contacts that are duplicates of something else