Finding largest integer in an array in JavaScript

var arr = [3, 6, 2, 56, 32, 5, 89, 32];
var largest = arr[0];

for (var i = 0; i < arr.length; i++) {
    if (largest < arr[i] ) {
        largest = arr[i];
    }
}
console.log(largest);

• You need to define i or else it become a global variable.
• Don't redefine largest in the loop.
• Since you're looping through the array, use i < array.length instead of i <= largest.
• Since you're comparing each of the items in the array to largest, use if(largest < array[i]) instead of if(array > largest)
• You should set largest equal to the first element in the array because what if all the numbers are negative?
• array is a bad variable name because it's too similar to Array (the array constructor). Try arr instead.

One liner:

var largest = Math.max.apply(0, array);

More info here: Javascript max() function for 3 numbers

The code below is fixed and should work. The problem was that in this line if (array>largest) { You were not providing the index of the array. By changing the code to this if (array[i]>largest) { it works. Notice that I added the [i] to the end of array in the if statement.

var array = [3 , 6, 2, 56, 32, 5, 89, 32];
var largest= 0;

for (i=0; i<array.length; i++){
    if (array[i]>largest) {
        largest=array[i];
    }
}




console.log(largest);