Finding local IP addresses using Python's stdlib

I just found this but it seems a bit hackish, however they say tried it on *nix and I did on windows and it worked.

import socket
s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
s.connect(("8.8.8.8", 80))
print(s.getsockname()[0])
s.close()

This assumes you have an internet access, and that there is no local proxy.

import socket
socket.gethostbyname(socket.gethostname())

This won't work always (returns 127.0.0.1 on machines having the hostname in /etc/hosts as 127.0.0.1), a paliative would be what gimel shows, use socket.getfqdn() instead. Of course your machine needs a resolvable hostname.

This method returns the "primary" IP on the local box (the one with a default route).

• Does NOT need routable net access or any connection at all.
• Works even if all interfaces are unplugged from the network.
• Does NOT need or even try to get anywhere else.
• Works with NAT, public, private, external, and internal IP's
• Pure Python 2 (or 3) with no external dependencies.
• Works on Linux, Windows, and OSX.

Python 3 or 2:

import socket
def get_ip():
    s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
    try:
        # doesn't even have to be reachable
        s.connect(('10.255.255.255', 1))
        IP = s.getsockname()[0]
    except Exception:
        IP = '127.0.0.1'
    finally:
        s.close()
    return IP

This returns a single IP which is the primary (the one with a default route). If you need instead all IP's attached to all interfaces (including localhost, etc), see this answer.

If you are behind a NAT firewall like your wifi box at home, then this will not show your public NAT IP, but instead your private IP on the local network which has a default route to your local WIFI router; getting your wifi router's external IP would either require running this on THAT box, or connecting to an external service such as whatismyip.com/whatismyipaddress.com that could reflect back the IP... but that is completely different from the original question. :)