finding the start and end index for a max sub array

Here is algorithm for maxsubarray:

public class MaxSubArray {

public static void main(String[] args) {
    int[] intArr={3, -1, -1, -1, -1, -1, 2, 0, 0, 0 };
    //int[] intArr = {-1, 3, -5, 4, 6, -1, 2, -7, 13, -3};
    //int[] intArr={-6,-2,-3,-4,-1,-5,-5};
    findMaxSubArray(intArr);
}

public static void findMaxSubArray(int[] inputArray){

    int maxStartIndex=0;
    int maxEndIndex=0;
    int maxSum = Integer.MIN_VALUE; 

    int cumulativeSum= 0;
    int maxStartIndexUntilNow=0;

    for (int currentIndex = 0; currentIndex < inputArray.length; currentIndex++) {

        int eachArrayItem = inputArray[currentIndex];

        cumulativeSum+=eachArrayItem;

        if(cumulativeSum>maxSum){
            maxSum = cumulativeSum;
            maxStartIndex=maxStartIndexUntilNow;
            maxEndIndex = currentIndex;
        }
        if (cumulativeSum<0){
            maxStartIndexUntilNow=currentIndex+1;
            cumulativeSum=0;
        }
    }

    System.out.println("Max sum         : "+maxSum);
    System.out.println("Max start index : "+maxStartIndex);
    System.out.println("Max end index   : "+maxEndIndex);
}

}

Fixing Carl Saldanha solution:

    int max_ending_here = 0;
    int max_so_far = 0;
    int _start = 0;
    int start = 0;
    int end = -1;

    for(int i=0; i<array.length; i++) {
        max_ending_here = max_ending_here + array[i];
        if (max_ending_here < 0) {
            max_ending_here = 0;
            _start = i+1;
        }

        if (max_ending_here > max_so_far) {
            max_so_far = max_ending_here;
            start = _start;
            end = i;
        }
    }

This is a C program to solve this problem. I think logic is same for all languages so I posted this answer.

void findMaxSubArrayIndex(){          
        int n,*a;
        int start=0,end=0,curr_max=0,prev_max=0,start_o=0,i;

        scanf("%d",&n);
        a = (int*)malloc(sizeof(int)*n);
        for(i=0; i<n; i++)  scanf("%d",a+i);

        prev_max = a[0];

        for(i=0; i<n; i++){
            curr_max += a[i];
            if(curr_max < 0){
                start = i+1;
                curr_max = 0;
            }
            else if(curr_max > prev_max){
                end = i;
                start_o = start;
                prev_max = curr_max;
            }

        }

        printf("%d %d \n",start_o,end); 
}