gdb Could not find operator[]
Try print by inner member of the vector.
print *(x._M_impl._M_start+0)
Here 0
is the index of data you want to inspect.
Inspired from this answer.
Alternately, you coud use the GDB extension below, which will poke at the std::vector
fields of GNU libstdc++ and thus works regardless of whether operator[]
is instantiated.
Load with:
(gdb) guile (load "the-file.scm")
This creates a new vref
command:
(gdb) vref my_vector 0
Code (requires GDB built with Guile support):
(use-modules (gdb)
(ice-9 match))
(define (std::vector-ref vector index)
(let* ((impl (value-field vector "_M_impl"))
(start (value-field impl "_M_start")))
(value-subscript start index)))
(define %vector-ref-command
(make-command "vref"
#:command-class COMMAND_OBSCURE
#:doc "Access an element of an std::vector."
#:invoke
(lambda (self args tty?)
(match (string-tokenize args)
((variable index)
(let* ((value (std::vector-ref (parse-and-eval variable)
(string->number index)))
(index (history-append! value)))
(format #t "$~a = ~a~%"
index (value-print value)))))
#t)))
(register-command! %vector-ref-command)
My understanding is that the compiler/linker includes only the member functions present in the source code and those are the ones I can use in gdb.
Your understanding is incorrect / incomplete.
std::vector
is a template class. Without explicit instantiation, the compiler is required to instantiate only the methods called (usually a subset of methods present in the source).
Is there a way to include every member function of std::vector so I can access them in gdb?
For a given type T
, you should be able to explicitly instantiate entire vector for that T
, by requesting it, e.g.:
template class std::vector<double>;