Get the CSRF token in test
After a long search (i've found nothing in doc and on the net about how to retrieve csrf token) i found a way:
$extract = $this->crawler->filter('input[name="element_add[_token]"]')
->extract(array('value'));
$csrf_token = $extract[0];
Extract the token from response before make the request.
CSRF token generator is normal symfony 2 service. You can get service and generate token yourself. For example:
$csrfToken = $client->getContainer()->get('form.csrf_provider')->generateCsrfToken('registration');
$crawler = $client->request('POST', '/ajax/register', array(
'fos_user_registration_form' => array(
'_token' => $csrfToken,
'username' => 'samplelogin',
'email' => 'sample@fake.pl',
'plainPassword' => array(
'first' => 'somepass',
'second' => 'somepass',
),
'name' => 'sampleuser',
'type' => 'DSWP',
),
));
The generateCsrfToken gets one important parameter intention which should be the same in the test and in the form otherwise it fails.
In symfony 3, in your WebTestCase
, you need to get the CSRF token:
$csrfToken = $client->getContainer()->get('security.csrf.token_manager')->getToken($csrfTokenId);
To get the $csrfTokenId
, the best way would be to force it in the options of your FormType
():
class TaskType extends AbstractType
{
// ...
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults(array(
'csrf_token_id' => 'task_item',
));
}
// ...
}
So in this case: $csrfTokenId = "task_item";
. Or you you can try to use the default value, that would be the name of your form.
Then use it as a post parameter:
$client->request(
'POST',
'/url',
[
'formName' => [
'field' => 'value',
'field2' => 'value2',
'_token' => $csrfToken
]
]
);