Graphically solving for complex roots -- how to visualize?

Here is a way.

Suppose that we want to visualize the roots of the cubic equation $$ z^3+z+1=0 $$

Write $z=x+iy$ and expand: \begin{align} (x+iy)^3+(x+iy)+1&=0\\ x^3+3ix^2y-3xy^2-iy^3+x+iy+1&=0\\ \end{align}

Taking real and imaginary parts, we get \begin{align} x^3-3xy^2+x+1&=0\\ 3x^2y-y^3+y&=0 \end{align} Plotting the solution sets of these two equations gives us two curves in the $xy$-plane:

Now, the original expression is zero if and only if its real and imaginary parts are both zero. In other words, the roots of our original polynomial correspond to the points of intersection of these two curves.

This trick can be used to visualize the roots of any complex function $f$. Just write it in the form $f(x+iy)=u(x,y)+iv(x,y)$ and plot the solution sets to $u(x,y)=0$ and $v(x,y)=0$. Then the roots will correspond to the intersections of these two curves.

I have developed a very clear method of visualizing where the complex roots of an equation are. The method involves drawing a graph of y = f(x) in the usual way on x, y plane but adding a 3rd axis to allow those special complex x values which also produce real y values. This means we have a normal y AXIS but a complex x PLANE. This is my first time on stackexchange so I cannot yet provide you with some excellent diagrams showing this method. I have however, just made a short video showing how the method works. I encouraging you to view it. Solutions of Cubics using Phantom Graphs http://screencast.com/t/dkAYxFDwH

Also, I have written a special section on this exact topic in my website: http://www.phantomgraphs.weebly.com just scroll right down to the last entry I have made especially for this question.