How can I encode a string to Base64 in Swift?
Swift
import Foundation
extension String {
func fromBase64() -> String? {
guard let data = Data(base64Encoded: self) else {
return nil
}
return String(data: data, encoding: .utf8)
}
func toBase64() -> String {
return Data(self.utf8).base64EncodedString()
}
}
I don’t have 6.2 installed but I don’t think 6.3 is any different in this regard:
dataUsingEncoding
returns an optional, so you need to unwrap that.
NSDataBase64EncodingOptions.fromRaw
has been replaced with NSDataBase64EncodingOptions(rawValue:)
. Slightly surprisingly, this is not a failable initializer so you don’t need to unwrap it.
But since NSData(base64EncodedString:)
is a failable initializer, you need to unwrap that.
Btw, all these changes were suggested by Xcode migrator (click the error message in the gutter and it has a “fix-it” suggestion).
Final code, rewritten to avoid force-unwraps, looks like this:
import Foundation
let str = "iOS Developer Tips encoded in Base64"
println("Original: \(str)")
let utf8str = str.dataUsingEncoding(NSUTF8StringEncoding)
if let base64Encoded = utf8str?.base64EncodedStringWithOptions(NSDataBase64EncodingOptions(rawValue: 0))
{
println("Encoded: \(base64Encoded)")
if let base64Decoded = NSData(base64EncodedString: base64Encoded, options: NSDataBase64DecodingOptions(rawValue: 0))
.map({ NSString(data: $0, encoding: NSUTF8StringEncoding) })
{
// Convert back to a string
println("Decoded: \(base64Decoded)")
}
}
(if using Swift 1.2 you could use multiple if-lets instead of the map)
Swift 5 Update:
import Foundation
let str = "iOS Developer Tips encoded in Base64"
print("Original: \(str)")
let utf8str = str.data(using: .utf8)
if let base64Encoded = utf8str?.base64EncodedString(options: Data.Base64EncodingOptions(rawValue: 0)) {
print("Encoded: \(base64Encoded)")
if let base64Decoded = Data(base64Encoded: base64Encoded, options: Data.Base64DecodingOptions(rawValue: 0))
.map({ String(data: $0, encoding: .utf8) }) {
// Convert back to a string
print("Decoded: \(base64Decoded ?? "")")
}
}
Swift 4.2
"abcd1234".data(using: .utf8)?.base64EncodedString()