How can I read inputs as numbers?
For multiple integer in a single line, map
might be better.
arr = map(int, raw_input().split())
If the number is already known, (like 2 integers), you can use
num1, num2 = map(int, raw_input().split())
In Python 3.x, raw_input
was renamed to input
and the Python 2.x input
was removed.
This means that, just like raw_input
, input
in Python 3.x always returns a string object.
To fix the problem, you need to explicitly make those inputs into integers by putting them in int
:
x = int(input("Enter a number: "))
y = int(input("Enter a number: "))
Solution
Since Python 3, input
returns a string which you have to explicitly convert to int
s, with int
, like this
x = int(input("Enter a number: "))
y = int(input("Enter a number: "))
You can accept numbers of any base and convert them directly to base-10 with the int
function, like this
>>> data = int(input("Enter a number: "), 8)
Enter a number: 777
>>> data
511
>>> data = int(input("Enter a number: "), 16)
Enter a number: FFFF
>>> data
65535
>>> data = int(input("Enter a number: "), 2)
Enter a number: 10101010101
>>> data
1365
The second parameter tells what is the base of the numbers entered and then internally it understands and converts it. If the entered data is wrong it will throw a ValueError
.
>>> data = int(input("Enter a number: "), 2)
Enter a number: 1234
Traceback (most recent call last):
File "<input>", line 1, in <module>
ValueError: invalid literal for int() with base 2: '1234'
For values that can have a fractional component, the type would be float
rather than int
:
x = float(input("Enter a number:"))
Differences between Python 2 and 3
Summary
- Python 2's
input
function evaluated the received data, converting it to an integer implicitly (read the next section to understand the implication), but Python 3'sinput
function does not do that anymore. - Python 2's equivalent of Python 3's
input
is theraw_input
function.
Python 2.x
There were two functions to get user input, called input
and raw_input
. The difference between them is, raw_input
doesn't evaluate the data and returns as it is, in string form. But, input
will evaluate whatever you entered and the result of evaluation will be returned. For example,
>>> import sys
>>> sys.version
'2.7.6 (default, Mar 22 2014, 22:59:56) \n[GCC 4.8.2]'
>>> data = input("Enter a number: ")
Enter a number: 5 + 17
>>> data, type(data)
(22, <type 'int'>)
The data 5 + 17
is evaluated and the result is 22
. When it evaluates the expression 5 + 17
, it detects that you are adding two numbers and so the result will also be of the same int
type. So, the type conversion is done for free and 22
is returned as the result of input
and stored in data
variable. You can think of input
as the raw_input
composed with an eval
call.
>>> data = eval(raw_input("Enter a number: "))
Enter a number: 5 + 17
>>> data, type(data)
(22, <type 'int'>)
Note: you should be careful when you are using input
in Python 2.x. I explained why one should be careful when using it, in this answer.
But, raw_input
doesn't evaluate the input and returns as it is, as a string.
>>> import sys
>>> sys.version
'2.7.6 (default, Mar 22 2014, 22:59:56) \n[GCC 4.8.2]'
>>> data = raw_input("Enter a number: ")
Enter a number: 5 + 17
>>> data, type(data)
('5 + 17', <type 'str'>)
Python 3.x
Python 3.x's input
and Python 2.x's raw_input
are similar and raw_input
is not available in Python 3.x.
>>> import sys
>>> sys.version
'3.4.0 (default, Apr 11 2014, 13:05:11) \n[GCC 4.8.2]'
>>> data = input("Enter a number: ")
Enter a number: 5 + 17
>>> data, type(data)
('5 + 17', <class 'str'>)