How do I conditionally add attributes to React components?
juandemarco's answer is usually correct, but here is another option.
Build an object how you like:
var inputProps = {
value: 'foo',
onChange: this.handleChange
};
if (condition) {
inputProps.disabled = true;
}
Render with spread, optionally passing other props also.
<input
value="this is overridden by inputProps"
{...inputProps}
onChange={overridesInputProps}
/>
Apparently, for certain attributes, React is intelligent enough to omit the attribute if the value you pass to it is not truthy. For example:
const InputComponent = function() {
const required = true;
const disabled = false;
return (
<input type="text" disabled={disabled} required={required} />
);
}
will result in:
<input type="text" required>
Update: if anyone is curious as to how/why this happens, you can find details in ReactDOM's source code, specifically at lines 30 and 167 of the DOMProperty.js file.
Here is an alternative.
var condition = true;
var props = {
value: 'foo',
...(condition && { disabled: true })
};
var component = <div {...props} />;
Or its inline version
var condition = true;
var component = (
<div value="foo" {...(condition && { disabled: true })} />
);
Here is an example of using Bootstrap's Button
via React-Bootstrap (version 0.32.4):
var condition = true;
return (
<Button {...(condition ? {bsStyle: 'success'} : {})} />
);
Depending on the condition, either {bsStyle: 'success'}
or {}
will be returned. The spread operator will then spread the properties of the returned object to Button
component. In the falsy case, since no properties exist on the returned object, nothing will be passed to the component.
An alternative way based on Andy Polhill's comment:
var condition = true;
return (
<Button bsStyle={condition ? 'success' : undefined} />
);
The only small difference is that in the second example the inner component <Button/>
's props
object will have a key bsStyle
with a value of undefined
.