How do I find my computer's IP address using the bash shell?

ifconfig en0 | grep inet | grep -v inet6

Output of above is expected to be in the following form:

inet 192.168.111.1 netmask 0xffffff00 broadcast 192.168.111.255

Add an awk statement to print the second column to avoid using cut (awk is a pretty standard unix tool):

ifconfig en0 | grep inet | grep -v inet6 | awk '{print $2}'

I use the following to get the current IP when on a LAN where the first few numbers of the IP are always the same (replace 192.168.111 with your own numbers):

ifconfig | grep 192.168.111 | awk '{print $2}'

To get the ip of another machine that you know the name of, try (replace hostname and 192.168.111 with your own values):

ping -c 1 hostname | grep 192.168.11 | grep 'bytes from' | awk '{print $4}' | sed 's/://g'

You might already be aware, but running

python manage.py runserver 0.0.0.0:8000

makes your machine visible to everyone on the network.

Is there a reason you'd need to specify your IP?

Thi should work as well as other commands I've already seen:

ifconfig eth0 | grep inet | awk '{print $2}' | cut -d':' -f2

• Replace eth0 with the desired interface (eth0, eth1, wlan0...)

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