How do I get the App version and build number using Swift?
Updated for Swift 3.0
The NS
-prefixes are now gone in Swift 3.0 and several properties/methods have changed names to be more Swifty. Here's what this looks like now:
extension Bundle {
var releaseVersionNumber: String? {
return infoDictionary?["CFBundleShortVersionString"] as? String
}
var buildVersionNumber: String? {
return infoDictionary?["CFBundleVersion"] as? String
}
}
Bundle.main.releaseVersionNumber
Bundle.main.buildVersionNumber
Old Updated Answer
I've been working with Frameworks a lot since my original answer, so I wanted to update my solution to something that is both simpler and much more useful in a multi-bundle environment:
extension NSBundle { var releaseVersionNumber: String? { return self.infoDictionary?["CFBundleShortVersionString"] as? String } var buildVersionNumber: String? { return self.infoDictionary?["CFBundleVersion"] as? String } }
Now this extension will be useful in apps to identify both the main bundle and any other included bundles (such as a shared framework for extension programming or third frameworks like AFNetworking), like so:
NSBundle.mainBundle().releaseVersionNumber NSBundle.mainBundle().buildVersionNumber // or... NSBundle(URL: someURL)?.releaseVersionNumber NSBundle(URL: someURL)?.buildVersionNumber
Original Answer
I wanted to improve on some of the answers already posted. I wrote a class extension that can be added to your tool chain to handle this in a more logical fashion.
extension NSBundle { class var applicationVersionNumber: String { if let version = NSBundle.mainBundle().infoDictionary?["CFBundleShortVersionString"]
as? String { return version } return "Version Number Not Available" }
class var applicationBuildNumber: String { if let build = NSBundle.mainBundle().infoDictionary?["CFBundleVersion"] as? String { return build } return "Build Number Not Available" } }
So now you can access this easily by:
let versionNumber = NSBundle.applicationVersionNumber
EDIT
Updated for Swift 4.2
let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String
EDIT
As pointed out by @azdev on the new version of Xcode you will get a compile error for trying my previous solution, to solve this just edit it as suggested to unwrap the bundle dictionary using a !
let nsObject: AnyObject? = Bundle.main.infoDictionary!["CFBundleShortVersionString"]
End Edit
Just use the same logic than in Objective-C but with some small changes
//First get the nsObject by defining as an optional anyObject
let nsObject: AnyObject? = NSBundle.mainBundle().infoDictionary["CFBundleShortVersionString"]
//Then just cast the object as a String, but be careful, you may want to double check for nil
let version = nsObject as! String