How to change Java version on Windows 10

java -version is running the wrong version of java.

Diagnostics:

>java -version
java version "1.8.0_66"
Java(TM) SE Runtime Environment (build 1.8.0_66-b18)
Java HotSpot(TM) 64-Bit Server VM (build 25.66-b18, mixed mode)

the following is the Java related contents from the output of PATH:

PATH=C:\ProgramData\Oracle\Java\javapath; ... C:\Program Files\Java\jdk1.6.0_45\bin

Conclusion:

From the above output we can deduce that C:\ProgramData\Oracle\Java\javapath is 1.8.0_66.

You need to change your PATH to put C:\Program Files\Java\jdk1.6.0_45\bin first.

I noticed that after checking the path per your suggestion. Windows 10 does not allow me to edit the path because it says "This environment variable is too large." I know there should be another question to deal with this separately.

You also need to clean up your path. My guess is you have a lot of duplicate entries.

I have the same problem, I have set JAVA_HOME:

C:\Program Files\Java\jdk1.7.0_75

and Path to:

%JAVA_HOME%\bin

I need run jdk 7. When I run java -version it always appear jdk 8.

I solved it with: in System Environment --> Path --> order %JAVA_HOME%\bin to first.

This is the REAL active JAVA executable into your PATH:

C:\Program Files (x86)\Common Files\Oracle\Java\javapath;

Remove it and the system take the value from

...;%JAVA_HOME%\bin\;