How to compare two NSDates: Which is more recent?

Let's assume two dates:

NSDate *date1;
NSDate *date2;

Then the following comparison will tell which is earlier/later/same:

if ([date1 compare:date2] == NSOrderedDescending) {
    NSLog(@"date1 is later than date2");
} else if ([date1 compare:date2] == NSOrderedAscending) {
    NSLog(@"date1 is earlier than date2");
} else {
    NSLog(@"dates are the same");
}

Please refer to the NSDate class documentation for more details.

In Swift, you can overload existing operators:

func > (lhs: NSDate, rhs: NSDate) -> Bool {
    return lhs.timeIntervalSinceReferenceDate > rhs.timeIntervalSinceReferenceDate
}

func < (lhs: NSDate, rhs: NSDate) -> Bool {
    return lhs.timeIntervalSinceReferenceDate < rhs.timeIntervalSinceReferenceDate
}

Then, you can compare NSDates directly with <, >, and == (already supported).

Late to the party, but another easy way of comparing NSDate objects is to convert them into primitive types which allows for easy use of '>' '<' '==' etc

eg.

if ([dateA timeIntervalSinceReferenceDate] > [dateB timeIntervalSinceReferenceDate]) {
    //do stuff
}

timeIntervalSinceReferenceDate converts the date into seconds since the reference date (1 January 2001, GMT). As timeIntervalSinceReferenceDate returns a NSTimeInterval (which is a double typedef), we can use primitive comparators.