How to convert a tree structure to a Stream of nodes in java
A more general approach using any node class is to add a parameter for the method, which returns the children:
public class TreeNodeStream {
public static <T> Stream<T> of(T node, Function<T, Collection<? extends T>> childrenFunction) {
return Stream.concat( //
Stream.of(node), //
childrenFunction.apply(node).stream().flatMap(n -> of(n, childrenFunction)));
}
}
An example using File:
TreeNodeStream.of(
new File("."), f -> f.isDirectory() ? Arrays.asList(f.listFiles()) :
Collections.emptySet())
.filter(f -> f.getName().endsWith(".java"))
.collect(Collectors::toList);
I find this implementation of stream()
which is a DFS tree traversal:
public class SelectTree<D> {
//...
public Stream<SelectTree<D>> stream() {
if (this.isLeaf()) {
return Stream.of(this);
} else {
return this.getChildren().stream()
.map(child -> child.stream())
.reduce(Stream.of(this), (s1, s2) -> Stream.concat(s1, s2));
}
}
}
If you can't change the tree implementation like for primefaces TreeNode
(org.primefaces.model.TreeNode
) you can define a method in an other class:
public Stream<TreeNode> stream(TreeNode parentNode) {
if(parentNode.isLeaf()) {
return Stream.of(parentNode);
} else {
return parentNode.getChildren().stream()
.map(childNode -> stream(childNode))
.reduce(Stream.of(parentNode), (s1, s2) -> Stream.concat(s1, s2)) ;
}
}
One small addition to kwisatz's answer.
This implementation:
this.getChildren().stream()
.map(SelectTree::stream)
.reduce(Stream.of(this), Stream::concat);
will be more eager, i. e. the whole hierarchy will be traversed during a stream creation. If your hirarchy is large and, let's say, you're looking for a single node matching some predicate, you may want a more lazy behaviour:
Stream.concat(Stream.of(this),
this.getChildren().stream().flatMap(SelectTree::stream));
In this case, only the children of the root node will be retrieved during a stream creation, and a search for a node won't necessarily result in the whole hierarchy being traversed.
Both approaches will exhibit the DFS iteration order.