How to decide font color in white or black depending on background color?
How about this (JavaScript code)?
/**
* Get color (black/white) depending on bgColor so it would be clearly seen.
* @param bgColor
* @returns {string}
*/
getColorByBgColor(bgColor) {
if (!bgColor) { return ''; }
return (parseInt(bgColor.replace('#', ''), 16) > 0xffffff / 2) ? '#000' : '#fff';
}
I take no credit for this code as it's not mine, but I leave it here for others to find quickly in the future:
Based on Mark Ransoms answer, here's a code snippet for the simple version:
function pickTextColorBasedOnBgColorSimple(bgColor, lightColor, darkColor) {
var color = (bgColor.charAt(0) === '#') ? bgColor.substring(1, 7) : bgColor;
var r = parseInt(color.substring(0, 2), 16); // hexToR
var g = parseInt(color.substring(2, 4), 16); // hexToG
var b = parseInt(color.substring(4, 6), 16); // hexToB
return (((r * 0.299) + (g * 0.587) + (b * 0.114)) > 186) ?
darkColor : lightColor;
}
and here's the code snippet for the advanced version:
function pickTextColorBasedOnBgColorAdvanced(bgColor, lightColor, darkColor) {
var color = (bgColor.charAt(0) === '#') ? bgColor.substring(1, 7) : bgColor;
var r = parseInt(color.substring(0, 2), 16); // hexToR
var g = parseInt(color.substring(2, 4), 16); // hexToG
var b = parseInt(color.substring(4, 6), 16); // hexToB
var uicolors = [r / 255, g / 255, b / 255];
var c = uicolors.map((col) => {
if (col <= 0.03928) {
return col / 12.92;
}
return Math.pow((col + 0.055) / 1.055, 2.4);
});
var L = (0.2126 * c[0]) + (0.7152 * c[1]) + (0.0722 * c[2]);
return (L > 0.179) ? darkColor : lightColor;
}
To use them just call:
var color = '#EEACAE' // this can be any color
pickTextColorBasedOnBgColorSimple(color, '#FFFFFF', '#000000');
Also, thanks Alx
and chetstone
.
Building on my answer to a similar question.
You need to break the hex code into 3 pieces to get the individual red, green, and blue intensities. Each 2 digits of the code represent a value in hexadecimal (base-16) notation. I won't get into the details of the conversion here, they're easy to look up.
Once you have the intensities for the individual colors, you can determine the overall intensity of the color and choose the corresponding text.
if (red*0.299 + green*0.587 + blue*0.114) > 186 use #000000 else use #ffffff
The threshold of 186 is based on theory, but can be adjusted to taste. Based on the comments below a threshold of 150 may work better for you.
Edit: The above is simple and works reasonably well, and seems to have good acceptance here at StackOverflow. However, one of the comments below shows it can lead to non-compliance with W3C guidelines in some circumstances. Herewith I derive a modified form that always chooses the highest contrast based on the guidelines. If you don't need to conform to W3C rules then I'd stick with the simpler formula above. For an interesting look into the problems with this see Contrast Ratio Math and Related Visual Issues.
The formula given for contrast in the W3C Recommendations (WCAG 2.0) is (L1 + 0.05) / (L2 + 0.05)
, where L1
is the luminance of the lightest color and L2
is the luminance of the darkest on a scale of 0.0-1.0. The luminance of black is 0.0 and white is 1.0, so substituting those values lets you determine the one with the highest contrast. If the contrast for black is greater than the contrast for white, use black, otherwise use white. Given the luminance of the color you're testing as L
the test becomes:
if (L + 0.05) / (0.0 + 0.05) > (1.0 + 0.05) / (L + 0.05) use #000000 else use #ffffff
This simplifies down algebraically to:
if L > sqrt(1.05 * 0.05) - 0.05
Or approximately:
if L > 0.179 use #000000 else use #ffffff
The only thing left is to compute L
. That formula is also given in the guidelines and it looks like the conversion from sRGB to linear RGB followed by the ITU-R recommendation BT.709 for luminance.
for each c in r,g,b:
c = c / 255.0
if c <= 0.04045 then c = c/12.92 else c = ((c+0.055)/1.055) ^ 2.4
L = 0.2126 * r + 0.7152 * g + 0.0722 * b
The threshold of 0.179 should not be changed since it is tied to the W3C guidelines. If you find the results not to your liking, try the simpler formula above.