How to get a sub array of array in Java, without copying data?

Arrays.asList(array).subList(x, y).

This method doesn't give you an array, but a List, which is far more flexible.

There is no real way to wrap any data without copying and receive real array in Java. You just cannot create new array over existing memory. You have basically 2 options:

• Use methods that can accept range of array. This was already recommended.
• Use wrapper that gives some kind of abstraction that is close to array and is suitable for many applications. Will be described below.

You may use java.nio.Buffer classes hierarchy, especially java.nio.ByteBuffer which offers buffer abstraction on whole array or sub-ranges. Often it is what people need. This also offers many interesting abilities like 'zero copy' flip and flexible byte area representation.

Here is example of wrapping using java.nio.ByteBuffer. This should be very close to what you need. At least for some operations.

byte [] a1 = {0, 0, 1, 0};
ByteBuffer buf = ByteBuffer.wrap(a1,1,2);

Then you can do on buf any ByteBuffer operation.

Just a warning, buf.array() returns original a1 array (backend) with all elements.

Many classes in Java accept a subset of an arrays as parameter. E.g. Writer.write(char cbuf[], int off, int len). Maybe this already suffices for your usecase.