How to get the Touch position in android?
@Override
public boolean onTouchEvent(MotionEvent event)
{
int x = (int)event.getX();
int y = (int)event.getY();
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
case MotionEvent.ACTION_MOVE:
case MotionEvent.ACTION_UP:
}
return false;
}
The three cases are so that you can react to different types of events, in this example tapping or dragging or lifting the finger again.
@Override
public boolean onTouch(View v, MotionEvent event) {
float x = event.getX();
float y = event.getY();
return true;
}
Supplemental answer
Given an OnTouchListener
private View.OnTouchListener handleTouch = new View.OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
int x = (int) event.getX();
int y = (int) event.getY();
switch (event.getAction()) {
case MotionEvent.ACTION_DOWN:
Log.i("TAG", "touched down");
break;
case MotionEvent.ACTION_MOVE:
Log.i("TAG", "moving: (" + x + ", " + y + ")");
break;
case MotionEvent.ACTION_UP:
Log.i("TAG", "touched up");
break;
}
return true;
}
};
set on some view:
myView.setOnTouchListener(handleTouch);
This gives you the touch event coordinates relative to the view that has the touch listener assigned to it. The top left corner of the view is (0, 0)
. If you move your finger above the view, then y
will be negative. If you move your finger left of the view, then x
will be negative.
int x = (int)event.getX();
int y = (int)event.getY();
If you want the coordinates relative to the top left corner of the device screen, then use the raw values.
int x = (int)event.getRawX();
int y = (int)event.getRawY();
Related
- How are Android touch events delivered?