How to make your push notification Open a certain view controller?
You can detect if the app opened from the notification with this code in app delegate. You will need to set the initial view controller when the application state is UIApplicationStateInactive
before the app has become active. You can perform any logic there to decide which view controller should be opened and what content should be shown in that view controller.
-(void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo fetchCompletionHandler:(void (^)(UIBackgroundFetchResult))completionHandler{
if(application.applicationState == UIApplicationStateActive) {
//app is currently active, can update badges count here
} else if(application.applicationState == UIApplicationStateBackground){
//app is in background, if content-available key of your notification is set to 1, poll to your backend to retrieve data and update your interface here
} else if(application.applicationState == UIApplicationStateInactive){
//app is transitioning from background to foreground (user taps notification), do what you need when user taps here
self.window = [[UIWindow alloc] initWithFrame:UIScreen.mainScreen.bounds];
UIStoryboard *storyboard = [UIStoryboard storyboardWithName:@"MainStoryboard" bundle:nil];
UIViewController *viewController = // determine the initial view controller here and instantiate it with [storyboard instantiateViewControllerWithIdentifier:<storyboard id>];
self.window.rootViewController = viewController;
[self.window makeKeyAndVisible];
}
}
Here is the Swift 3 Version with switch/case instead of if/else
open func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable: Any]) {
switch application.applicationState {
case .active:
print("do stuff in case App is active")
case .background:
print("do stuff in case App is in background")
case .inactive:
print("do stuff in case App is inactive")
}
}