How to map and remove nil values in Ruby

You could use compact:

[1, nil, 3, nil, nil].compact
=> [1, 3] 

---

I'd like to remind people that if you're getting an array containing nils as the output of a map block, and that block tries to conditionally return values, then you've got code smell and need to rethink your logic.

For instance, if you're doing something that does this:

[1,2,3].map{ |i|
  if i % 2 == 0
    i
  end
}
# => [nil, 2, nil]

Then don't. Instead, prior to the map, reject the stuff you don't want or select what you do want:

[1,2,3].select{ |i| i % 2 == 0 }.map{ |i|
  i
}
# => [2]

I consider using compact to clean up a mess as a last-ditch effort to get rid of things we didn't handle correctly, usually because we didn't know what was coming at us. We should always know what sort of data is being thrown around in our program; Unexpected/unknown data is bad. Anytime I see nils in an array I'm working on, I dig into why they exist, and see if I can improve the code generating the array, rather than allow Ruby to waste time and memory generating nils then sifting through the array to remove them later.

'Just my $%0.2f.' % [2.to_f/100]

Try using reduce or inject.

[1, 2, 3].reduce([]) { |memo, i|
  if i % 2 == 0
    memo << i
  end

  memo
}

I agree with the accepted answer that we shouldn't map and compact, but not for the same reasons.

I feel deep inside that map then compact is equivalent to select then map. Consider: map is a one-to-one function. If you are mapping from some set of values, and you map, then you want one value in the output set for each value in the input set. If you are having to select before-hand, then you probably don't want a map on the set. If you are having to select afterwards (or compact) then you probably don't want a map on the set. In either case you are iterating twice over the entire set, when a reduce only needs to go once.

Also, in English, you are trying to "reduce a set of integers into a set of even integers".